This site is now in read-only archive mode. Please move all discussion, and create a new account at the new Victron Community site.
Following scenario:
- MultiPlus-II 48/3000
- AC-In connected to public power grid (1)
- connected to big battery (48V LiFePo4) (2)
- AC-Out connected to internal grid (3)
How much power is available on (3)? Is this
- the max power from (1) plus 2.400 Watt (see datasheet below), so something like 10.000 Watt.
- only the power the inverter can generate, so 2.400 Watt?
It will be 32 amp .
Is this what the "Transfer switch: 32A" in the datasheet means?
That is correct.
However if it is inverting (no grid) it can only do the 2400W continuously at 25°C. (So closer to 10-11A)
So if you do have bigger loads out them on AC2, as it switches off (unless programmed different) automatically on grid loss.
It is sized like that so you can run your full loads and charge battery at the same time.
> However if it is inverting (no grid) it can only do the 2400W continuously at 25°C. (So closer to 10-11A)
This is understood.
Basically I wanted to know if I am also limited to this 2.400 W when connected to the grid. Happy to hear that I am not (and have 32A x 230V available).
Additional question: If I run higher loads, say 5.000W, and I programmed the MP2 to assist with power from the grid when the load > 2.000W, what happens?
Does it still invert and use 2.000W from my battery PLUS draw 3.000W from the public grid so that it can fulfill my 5.000W demand? Or does it pull the full 5.000W from the public grid and stop inverting?
There are a balance of settings for that, including depth of discharge (in SOC) from.the battery.
But to only draw the 5000 from grid you set the input current limit down to 5000 ÷ 230v or whatever your hrid voltage is at regularly
If you are running ESS assistant, you are not able to set the amount of power assist. The system does it for you based on the other parameters you set.
> But to only draw the 5000 from grid
No, this is not what I want to do - this is what I want to avoid :-D
Example:
Required: 6.000W (dish washer + oven + hairdryer for example)
Available from my battery/MP2: 2.400W
Needed from public grid: 3.600W
What happens here: Does the MP2 pull the full 6.000W from the public grid? Or can it invert the 2.400W by itself and only pull the missing 3.600W from the public grid?
