Arduino to VRM Example

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masoos asked Sep 2, '23

Arduino to VRM Example

Hi, I'm searching for a basic Arduino code example, but there is nothing yet. very confusing after all these years.....

Here is my code, which does not work...I always get "Fehler beim Abrufen der Daten" means the else path of the HTTP_Code_OK. Can someone please teach me??

Thanks

----------

void loop() {

if(wifiMulti.run() == WL_CONNECTED) {

String url = "https://vrmapi.victronenergy.com/v2/full";
HTTPClient http;
http.addHeader("x-authorization:", "eyJ0eAiOiJKV1QiLCJhbGciOiJSUzI1NiIsImp0aSI6IjgwY2NhN2VhYjYyNWZlNjVmZmM4YTI1ZTY2OTIxODQ2In0.eyJ1aWQiOiIzNTMyOTgiLCJ0b2tlbl90eXBlIjoiZGVmYXVsdCIsImlzcyI6InZybWFwaS52aWN0cm9uZW5lcmd5LmNvbSIsImF1ZCI6Imh0dHBzOi8vdnJtYXBpLnZpY3Ryb25lbmVyZ3kuY29tLyIsImlhdCI6MTY5MzY1MzkyMCwiZXhwIjoxNjkzNzQwMzIwLCJqdGkiOiI4MGNjYTdlYWI2MjVmZTY1ZmZjOGEyNWU2NjkyMTg0NiJ9.ZSNaayziK_8zlwfGktiHvnNe1WrXSRk3GtvaTvT0x5kqbvXBkHYY6UmuQ6lq6xtz4VIbzl-BEO1bmBf3udMd5km2i-uSXe64KAOoEbXM-fCpmn_B7b64h3AxMH8ApPUm4YUwVeChcaQzfHbMQLrcOtyyn8g4b5eylDLvhLhs8pq3_HnuzS-7aH-SkJttzena1A1NgjJed4An096DoNOzaZF_To7p0F0ocqRCaK9pIllYVOgKovC-rLJvs1j3NX-iIm1tFsQ8CRMxWVm9rZ7RsjOxFwNl2SzR2Imk_5BcceQXVlrLVwvxPVXyIOTPGl-iIbFNlkH5-gUmrfVLVvUQ"); // Ihr Authentifizierungstoken

http.begin(url);

int httpResponseCode = http.GET();

if (httpResponseCode == HTTP_CODE_OK) {

String payload = http.getString();

Serial.println(payload);

} else {

Serial.println("Fehler beim Abrufen der Daten");

}

http.end();

} else {

Serial.println("Verbindung zum WLAN verloren, erneuter Verbindungsversuch...");

}

delay(5000);

}

VRM arduino

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kevgermany ♦♦ commented · Sep 03, 2023 at 05:25 AM

@masoos

Moved to modifications space.

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Modifications Space

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Answer 1 · 2023-09-05T11:13:48Z

matt1309 answered · Sep 05, 2023 at 11:13 AM

Hi @masoos

ChatGPT will be your friend here.

However an easy debug is in your else statement to add Serial.println(httpResponseCode);

This will at least give you the error. It may be due to lack of Content-type header.

ie adding another header ('Content-Type: application/json')

I'm not familiar with Victron API, there may be other required headers also but printing the response code should give you a good idea.

I would test the API call using a tool like CURL then when you know you're getting the data you want translate the curl command into C++/arduino code.

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Answer 2 · 2023-09-08T09:42:30Z

masoos answered · Sep 08, 2023 at 09:42 AM

I'm sorry. I need to inform you, that this code was propsed by ChatGPT. I tried with several http.addHeaders, w/o success.

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matt1309 commented · Sep 08, 2023 at 10:39 AM

Hi @masoos

What debugging steps have you done?

Are you sure it's your code and not the request itself that's wrong?

Here's the steps I would take to debug:

1. Get a working api request to VRM, that you know works, using curl!

This will confirm if the issues are with your code or with what you're requesting. At the moment it could just be the token/authentication header is wrong. Or the endpoint of https://vrmapi.victronenergy.com/v2/full is wrong.

I would highly recommend using curl for this. Once you've got a curl command working and returning data, turning that into C++ will be easy. (chatGPT would literally do that for you...)

2. As I mentioned before print httpResponseCode in the else statement. Otherwise you have no idea what responseCode you're receiving. This will likely help a lot with what's going wrong with the request.

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Answer 3 · 2023-09-10T06:58:38Z

excalibur83 answered · Sep 10, 2023 at 06:58 AM

Hello,

are you sure httpResponseCode should be declared as int (Integer) ?

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masoos commented · Sep 11, 2023 at 06:54 AM

yes, result is "401"

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Answer 4 · 2023-09-11T06:56:52Z

masoos answered · Sep 11, 2023 at 06:56 AM

I also tried with other endpoint and now auth with email....

-------------------------------

HTTPClient http;

String payload = "{\"username\":\"m@s....\",\"password\":\"123....\"}";

http.sendRequest();

http.post("/v2/auth/login");

http.sendHeader("Content-Type", "application/json");

http.sendHeader("Content-Length", payload.length());

http.beginBody();

http.print(payload);

http.endRequest();

int statusCode = http.responseStatusCode();

String response = http.responseBody();

Serial.print("HTTP-Statuscode: ");

Serial.println(statusCode);

Serial.print("Antwort vom Server: ");

Serial.println(response);

-----------------

does not work either. hmmmmm

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matt1309 commented · Sep 11, 2023 at 08:13 AM

what response/status code are you getting?

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masoos matt1309 commented · Sep 13, 2023 at 09:10 PM

Again 401....

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matt1309 masoos commented · Sep 13, 2023 at 10:26 PM

Hi @masoos

payload.length i think needs to be a string in the header.

Try:

HTTPClient http;
String payload = "{\"username\":\"m@s....\",\"password\":\"123....\"}";

http.begin("https://vrmapi.victronenergy.com/v2/auth/login"); // Set the target URL

http.addHeader("Content-Type", "application/json");
http.addHeader("Content-Length", String(payload.length()));

int statusCode = http.POST(payload); // Send the POST request with the payload

// Print status code and response
Serial.print("HTTP-Statuscode: ");
Serial.println(statusCode);
String response = http.getString();
Serial.println(response);

http.end(); // Close the connection

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Answer 5 · 2023-09-16T19:56:37Z

masoos answered · Sep 16, 2023 at 07:56 PM

OK, this worked!

Result:

HTTP status code: 200

{"token":"xxxx","idUser":yyyyy,"verification_mode":"password","verification_sent":false}

200 is http okay.
I think I can continue like this now.

Question: what does "verification_sent":false}" mean exactly? Do I have to verify myself with token, or is mail/PW enough? Or to put it another way, when do I have to take tokens instead?

Thank you very much for your efforts

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