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samuil avatar image
samuil asked

Is my solar panel sufficient for my power consumption?

Hi,


whatsapp-image-2022-11-14-at-204710.jpg


Would you be able to tell me if my solar panel yield is suitable based on the consumption readings? Am I correct to assume today I consumed the exact amount of power my solar panel yielded? It is summer here in Australia I am just worried about winter.


My battery is 9Ah LifePo4 and my solar panel is 50W.


Kind regards!

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2 Answers
nickdb avatar image
nickdb answered ·

You have a 50W panel and produced 50Wh, which would be 1 hour of your panel at max production or 2 hours at 25W.

In a typical day you should be generating much more than this, assuming you are using it.

Your peak production is 26-43W, so it looks like it is working ok.

If you are only using 40-60Wh then you should have plenty of capacity left.

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samuil avatar image samuil commented ·

Can you please elaborate on 'You have a 50W panel and produced 50Wh, which would be 1 hour of your panel at max production or 2 hours at 25W.'

Does this mean my solar panel will generate 50Watts per hour, for approximately 'x' amount per day at 100% efficiency? From what I read max production would be typically four hours of the day. Meaning I would generate 200Watts of power in a period of 4 hours?

As Albert mentioned below, my battery has a total of 115W (12.8 x 9). Does this mean I would need 2 hours to charge the battery in full from depletion?


Sorry I am new to this stuff :)

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nickdb avatar image nickdb ♦♦ samuil commented ·

Effectively, yes. Wh (Watt hours) are the number of watts multiplied by the number of hours.

Obviously, what panels produce varies - by weather, season and temperature (the hotter the more they derate above 25C).

Conversely in winter, when there is less sunlight, they are more efficient due to cooler temps.

It is rare to get full power, especially at higher temperatures.

PV is a bell curve, like so (southern hemisphere).

screenshot-2022-11-23-at-152734.png

If you got an hour at quarter power, an hour half power, and lets assume 75% for 4 hours, then half, then a quarter again (8 hours of light), you would get a yield of around 225Wh, or around 16AH (at 14V).


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albert avatar image
albert answered ·

Your panel seems to be fine for what you are using. I am just wondering if your battery is large enough though. You have a 9Ah LFP battery, so 9 x 4 x 3.2 = 115Wh.

If your consumption stays at this level, you discharge about 40-50% of your battery capacity, so no problem. But what happens on days when you use more than you produce and your solar cannot fully recharge the battery?

Looking back through my (grid connected) Fronius data I saw that I had hardly any yield (daily yield of about 25% of Wp installed) for a few days earlier this year (Brisbane), when we had continuous rain.

I understand you have a 50W panel, so your Wp is 50W. If you also have 25% yield on similar days as we had, that would be 12.5Wh/day, which is not enough. Your battery would be discharged in 2 days.

You can either add panels but you probably need a larger charge controller (higher voltage/current rating) for that. Also, if you keep the 9Ah battery you would have to throttle the larger charge controller on days of full sun, otherwise you will cook your battery (too high charging amps).

Probably easier to get a larger battery (or add one or more identical ones in parallel). At 50Wh usage it will remain nearly full most of the time, but has the capacity to let you drain it on days when solar yield is low.

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samuil avatar image samuil commented ·

screenshot-2022-11-24-001823.png


In Sydney, Australia we have an average sunshine hours of 6-8 hours.

Would 25% efficiency still render me below the required charge?

Thank you very much for your help!

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